Example: crack growth (fracture mechanics)
This example explains how to solve a problem from linear fracture mechanics
with MasterAllRound. The equation includes exponents.
In linear fracture mechanics, the crack growth can be solved by integrating the
Paris law:
with
where K is the stress intensity factor and Y the compliance function, describing the geometry of the structure in which the crack exists.
For some cases, Y is constant and independent of the crack length.
Using this assumption is also a quick way to assess the performance of a structure.
For a constant Y, the integration for m ≠ 2 is straightforward and leads to:
Given the following input data:
 Stress range ΔS in [MPa]: 310
 Initial crack size a_{i} in [m]: 0.8E3
 Final crack size a_{f} in [m]: 8E3
 C = 1.059E11 [m/Zyklen]
 Y = 1.12
 m = 3
The input and result (N = 19590) in MasterAllRound are:
(To basic example)
(To example eigenfrequency computation)
(To MAR Cal)
(To MAR Plus)
